What is the domain of 3-sqrt(2x+1) ?

The domain of 3-sqrt(2x+1) is x>=-1/2

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domain of 3-sqrt(2x+1)

domain

3 - 2 x + 1

x \geq - \frac{1}{2}

Interval Notation

[- \frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{1}{2}

The function domain

x \geq - \frac{1}{2}

x^{2} + 9, x \geq 0

y = x (1 - x^{2})^{2}

f (x, y) = ln (x) - ln (x) sin (x)

f (x) = \frac{4 x}{3} + 12

g (x) = \frac{1}{x ^{2} - 2}