What is the domain of g(x)= 1/(x^2-2) ?

The domain of g(x)= 1/(x^2-2) is x sqrt(2)

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domain of g(x)= 1/(x^2-2)

domain

g (x) = \frac{1}{x ^{2} - 2}

x < - 2 or - 2 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2

The function domain

x < - 2 or - 2 < x < 2 or x > 2

f (x) = e^{x + 2} - 3

f (x) = sin (x) + 3

f (x) = sin (x) + 1

y = \frac{x + 3}{4 - x ^{2} - 9}

f (x) = - x^{2} + 8 x - 13

What is the domain of g(x)= 1/(x^2-2) ?
The domain of g(x)= 1/(x^2-2) is x<-sqrt(2)\lor-sqrt(2)<x<sqrt(2)\lor x>sqrt(2)