What is the domain of f(x)=(2x^2+3x-9)/(2x^2-32) ?

The domain of f(x)=(2x^2+3x-9)/(2x^2-32) is x 4

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domain of f(x)=(2x^2+3x-9)/(2x^2-32)

domain

f (x) = \frac{2 x ^{2} + 3 x - 9}{2 x ^{2} - 32}

x < - 4 or - 4 < x < 4 or x > 4

Interval Notation

(- \infty, - 4) \cup (- 4, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = - 4

The function domain

x < - 4 or - 4 < x < 4 or x > 4

f (x) = e^{x^{3} + 1}

\frac{x ^{2} - 16}{x}

\frac{3 x}{x + 2}

f (x) = cos (t - 2)

4 + x - 3

What is the domain of f(x)=(2x^2+3x-9)/(2x^2-32) ?
The domain of f(x)=(2x^2+3x-9)/(2x^2-32) is x<-4\lor-4<x<4\lor x>4