What is the domain of f(x)=2+(1+x)/(sqrt(9-x^2)) ?

The domain of f(x)=2+(1+x)/(sqrt(9-x^2)) is -3<x<3

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domain of f(x)=2+(1+x)/(sqrt(9-x^2))

domain

f (x) = 2 + \frac{1 + x}{9 - x ^{2}}

- 3 < x < 3

Interval Notation

(- 3, 3)

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 3

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

- 3 < x < 3

f (x) = 2 x^{2} + 5 x - 4

ln (2 x + 1)

f (x) = 4^{x} - 2

12 x

f (x) = \frac{4 x}{x ( x ^{2} - 16 )}

What is the domain of f(x)=2+(1+x)/(sqrt(9-x^2)) ?
The domain of f(x)=2+(1+x)/(sqrt(9-x^2)) is -3<x<3