What is the domain of f(x)=sqrt(x^2-8x) ?

The domain of f(x)=sqrt(x^2-8x) is x = 8

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domain of f(x)=sqrt(x^2-8x)

domain

f (x) = x^{2} - 8 x

x \leq 0 or x \geq 8

Interval Notation

(- \infty, 0] \cup [8, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 8

The function domain

x \leq 0 or x \geq 8

\frac{x ^{2} - 4}{x ^{2} - 9}

f (x) = \frac{5 x + 1}{x ^{3} - x ^{2} - 8 x}

f (x) = 3 x^{2} - 2 x + 1

f (x) = 18 - 3 x - x^{2}

y = x - 7

What is the domain of f(x)=sqrt(x^2-8x) ?
The domain of f(x)=sqrt(x^2-8x) is x<= 0\lor x>= 8