What is the domain of f(x)= 1/(sqrt(4.7x-7.5x^2)) ?

The domain of f(x)= 1/(sqrt(4.7x-7.5x^2)) is 0<x< 47/75

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domain of f(x)= 1/(sqrt(4.7x-7.5x^2))

domain

f (x) = \frac{1}{4.7 x - 7.5 x ^{2}}

0 < x < \frac{47}{75}

Interval Notation

(0, \frac{47}{75})

Solution steps

Find non-negative values for radicals:

0 \leq x \leq \frac{47}{75}

Find undefined (singularity) points:

x = 0, x = \frac{47}{75}

Combine real regions and undefined points for final function domain

0 < x < \frac{47}{75}

x^{3} + x^{2} - x - 1

f (x) = 4 - 3 x

\frac{x}{9 + x ^{2}}

x - x^{3}

f (x) = \frac{x + 2}{6 - x}

What is the domain of f(x)= 1/(sqrt(4.7x-7.5x^2)) ?
The domain of f(x)= 1/(sqrt(4.7x-7.5x^2)) is 0<x< 47/75