What is the distance (1,26),((13pi)/3 ,26) ?

The distance (1,26),((13pi)/3 ,26) is (13pi)/3-1

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distance (1,26),((13pi)/3 ,26)

distance

(1, 26), (\frac{13 π}{3}, 26)

\frac{13 π}{3} - 1

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(1, 26)

and

(\frac{13 π}{3}, 26)

= (\frac{13 π}{3} - 1)^{2} + (26 - 26)^{2}

Simplify

= \frac{13 π}{3} - 1

f (x) = \frac{x ^{2}}{x ^{2} - 16}

12 x

(- 2, 5), (4, 0)

f (x) = 6 cos (3 x + \frac{π}{2})

f (x) = x^{3} - 6 x^{2} + 4

What is the distance (1,26),((13pi)/3 ,26) ?
The distance (1,26),((13pi)/3 ,26) is (13pi)/3-1