What is the domain of f(x)=(2x-1)/(x^2+1) ?

The domain of f(x)=(2x-1)/(x^2+1) is -infinity <x<infinity

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domain of f(x)=(2x-1)/(x^2+1)

domain

f (x) = \frac{2 x - 1}{x ^{2} + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{x ^{2} - 64}{x ^{2} - 1}

y = 2 sin (2 x)

\frac{x ^{2} - 9}{x + 9}

ln (2 - x)

f (x) = 2 x^{5} - 6 x^{3} + 8 x^{2} - 5

What is the domain of f(x)=(2x-1)/(x^2+1) ?
The domain of f(x)=(2x-1)/(x^2+1) is -infinity <x<infinity