What is the domain of f(x)=(1+2/x)sqrt(x+6) ?

The domain of f(x)=(1+2/x)sqrt(x+6) is -6 0

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domain of f(x)=(1+2/x)sqrt(x+6)

domain

f (x) = (1 + \frac{2}{x}) x + 6

- 6 \leq x < 0 or x > 0

Interval Notation

[- 6, 0) \cup (0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 6

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 6 \leq x < 0 or x > 0

f (x) = 4 - 3 sin (4 x - 2)

y = \frac{4 x ^{2} + 7 x - 12}{x ^{2} - 2 x - 8}

f (x) = 6 + (ln (x^{2} - 9))^{2}

\frac{1}{ln ( x + x )}

x^{3} - x^{2}

What is the domain of f(x)=(1+2/x)sqrt(x+6) ?
The domain of f(x)=(1+2/x)sqrt(x+6) is -6<= x<0\lor x>0