What is the domain of f(x)= 1/(sqrt(7.4x-8.3x^2)) ?

The domain of f(x)= 1/(sqrt(7.4x-8.3x^2)) is 0<x< 74/83

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domain of f(x)= 1/(sqrt(7.4x-8.3x^2))

domain

f (x) = \frac{1}{7.4 x - 8.3 x ^{2}}

0 < x < \frac{74}{83}

Interval Notation

(0, \frac{74}{83})

Solution steps

Find non-negative values for radicals:

0 \leq x \leq \frac{74}{83}

Find undefined (singularity) points:

x = 0, x = \frac{74}{83}

Combine real regions and undefined points for final function domain

0 < x < \frac{74}{83}

lo g_{2} (4 x - 6)

f (x) = lo g_{4} (x + 1)

f (x) = \frac{x ^{2} - 3 x - 28}{x + 2}

3 x^{2} + 1

f (x) = 3 x^{4} - 2 x^{2} + 5

What is the domain of f(x)= 1/(sqrt(7.4x-8.3x^2)) ?
The domain of f(x)= 1/(sqrt(7.4x-8.3x^2)) is 0<x< 74/83