What is the domain of f(x)= 1/(sqrt(x+8)) ?

The domain of f(x)= 1/(sqrt(x+8)) is x>-8

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domain of f(x)= 1/(sqrt(x+8))

domain

f (x) = \frac{1}{x + 8}

x > - 8

Interval Notation

(- 8, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 8

Find undefined (singularity) points:

x = - 8

Combine real regions and undefined points for final function domain

x > - 8

f (x) = 8 - x^{2}

f (x) = 3^{x + 3}

f (x) = x^{2} + x - 1

f (x) = 2 cos (x)

f (x) = 15 - 2 x - x^{2}

What is the domain of f(x)= 1/(sqrt(x+8)) ?
The domain of f(x)= 1/(sqrt(x+8)) is x>-8