What is the domain of f(x)=(2x^2)/(x+1) ?

The domain of f(x)=(2x^2)/(x+1) is x -1

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domain of f(x)=(2x^2)/(x+1)

domain

f (x) = \frac{2 x ^{2}}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = - 2^{x} + 3

f (x) = \frac{2 x ^{2}}{x + 2}

f (x) = \frac{x - 4}{x ^{2}}

f (x) = \frac{2}{4 - x}

2 cos (\frac{1}{4}) y - 3

What is the domain of f(x)=(2x^2)/(x+1) ?
The domain of f(x)=(2x^2)/(x+1) is x<-1\lor x>-1