What is the domain of f(x)= 1/((x+5)(x-2)(x-7)) ?

The domain of f(x)= 1/((x+5)(x-2)(x-7)) is x 7

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domain of f(x)= 1/((x+5)(x-2)(x-7))

domain

f (x) = \frac{1}{( x + 5 ) ( x - 2 ) ( x - 7 )}

x < - 5 or - 5 < x < 2 or 2 < x < 7 or x > 7

Interval Notation

(- \infty, - 5) \cup (- 5, 2) \cup (2, 7) \cup (7, \infty)

Solution steps

Find undefined (singularity) points:

x = - 5, x = 2, x = 7

The function domain

x < - 5 or - 5 < x < 2 or 2 < x < 7 or x > 7

f (x) = - 1.1

\frac{6 + 7 x}{x - 1}

f (x) = \frac{- 6}{25 x ^{2} - 4}

f (x) = \frac{x}{4 - x} - \frac{2}{x ^{2} - 5 x}

f (x) = lo g_{10} (3 - 2 x) + 5

What is the domain of f(x)= 1/((x+5)(x-2)(x-7)) ?
The domain of f(x)= 1/((x+5)(x-2)(x-7)) is x<-5\lor-5<x<2\lor 2<x<7\lor x>7