What is the domain of y= 1/(sqrt(4-x^2)) ?

The domain of y= 1/(sqrt(4-x^2)) is -2<x<2

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domain of y= 1/(sqrt(4-x^2))

domain

y = \frac{1}{4 - x ^{2}}

- 2 < x < 2

Interval Notation

(- 2, 2)

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 2

Find undefined (singularity) points:

x = 2, x = - 2

Combine real regions and undefined points for final function domain

- 2 < x < 2

350000 \cdot csc (\frac{π}{30} x)

f (x) = 2 x - 3, x \geq 2

\frac{x ^{2} - 81}{3 x - 8}

f (x) = ln ∣ x + 2 ∣

- \frac{4}{5} x + 1

What is the domain of y= 1/(sqrt(4-x^2)) ?
The domain of y= 1/(sqrt(4-x^2)) is -2<x<2