What is the domain of f(x)=x^2+x,x>= 1/2 ?

The domain of f(x)=x^2+x,x>= 1/2 is x>= 1/2

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domain of f(x)=x^2+x,x>= 1/2

domain

f (x) = x^{2} + x, x \geq \frac{1}{2}

x \geq \frac{1}{2}

Interval Notation

[\frac{1}{2}, \infty)

Solution steps

Set the domain to the given interval

x \geq \frac{1}{2}

The function has no undefined points nor domain constraints. Therefore, the domain is

x \geq \frac{1}{2}

g (x) = \frac{3 x}{4 - x}

\frac{7}{x ( x - 4 )}

\frac{9 x - 18}{x ^{2} - 5 x + 4}

f (x) = \frac{1}{1 + ln ( x )}

y = arcsin (x - 3)

What is the domain of f(x)=x^2+x,x>= 1/2 ?
The domain of f(x)=x^2+x,x>= 1/2 is x>= 1/2