What is the domain of f(x)=sqrt(t+8) ?

The domain of f(x)=sqrt(t+8) is t>=-8

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domain of f(x)=sqrt(t+8)

domain

f (x) = t + 8

t \geq - 8

Interval Notation

[- 8, \infty)

Solution steps

Find non-negative values for radicals:

t \geq - 8

The function domain

t \geq - 8

e^{2}

f (x) = 6 + (ln (x^{2} - 25))^{2}

\frac{3 x + 3}{x + 5}

\frac{x ^{2} + x - 2}{x ^{2} - x - 6}

f (x) = 3 - x^{2}