What is the domain of y=4+sqrt((x-2)) ?

The domain of y=4+sqrt((x-2)) is x>= 2

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domain of y=4+sqrt((x-2))

domain

y = 4 + (x - 2)

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

f (x) = x sin (x)

\frac{7}{4 x + 12}

\frac{( n - 1 ) ( - 1 ) ^{n + 1}}{2 n + 3}

f (x) = \frac{x ^{2} + 4}{x ^{2} - 4}

f (x) = \frac{1 + x}{1 - x}