What is the domain of f(x)= 1/(sqrt(2x-1)) ?

The domain of f(x)= 1/(sqrt(2x-1)) is x> 1/2

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domain of f(x)= 1/(sqrt(2x-1))

domain

f (x) = \frac{1}{2 x - 1}

x > \frac{1}{2}

Interval Notation

(\frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{2}

Find undefined (singularity) points:

x = \frac{1}{2}

Combine real regions and undefined points for final function domain

x > \frac{1}{2}

\frac{x - 2}{3}

\frac{x}{8 x - 7}

f (x) = \frac{1}{( 1 - x + 5 )}

\frac{- 1}{x - 2}

f (x) = \frac{3 x - 4}{x ^{2} - 3 x - 4}

What is the domain of f(x)= 1/(sqrt(2x-1)) ?
The domain of f(x)= 1/(sqrt(2x-1)) is x> 1/2