What is the domain of f(x)=3-sqrt(4-x^2) ?

The domain of f(x)=3-sqrt(4-x^2) is -2<= x<= 2

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domain of f(x)=3-sqrt(4-x^2)

domain

f (x) = 3 - 4 - x^{2}

- 2 \leq x \leq 2

Interval Notation

[- 2, 2]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 2

The function domain

- 2 \leq x \leq 2

f (x) = e^{x} + e^{- x}

\frac{2 ^{4 x - 1} \cdot 3 ^{x - 2}}{1 2 ^{x - 2}}

lo g_{2} (x^{2} - 1)

ln (2 t - 1)

\frac{3 x - 1}{2 x + 3}

What is the domain of f(x)=3-sqrt(4-x^2) ?
The domain of f(x)=3-sqrt(4-x^2) is -2<= x<= 2