What is the domain of y=sqrt((x+1)/(x-1)) ?

The domain of y=sqrt((x+1)/(x-1)) is x 1

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domain of y=sqrt((x+1)/(x-1))

domain

y = \frac{x + 1}{x - 1}

x \leq - 1 or x > 1

Interval Notation

(- \infty, - 1] \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x > 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x \leq - 1 or x > 1

\frac{9}{7 x - 2}

f (x) = lo g_{10} (x) - 3

\frac{2 x - 6}{x - 4}

f (x) = 5 x + 5

f (x) = \frac{x - 5}{2 x - 4}

What is the domain of y=sqrt((x+1)/(x-1)) ?
The domain of y=sqrt((x+1)/(x-1)) is x<=-1\lor x>1