What is the domain of f(x)=(x-5)/(x^2-9) ?

The domain of f(x)=(x-5)/(x^2-9) is x 3

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domain of f(x)=(x-5)/(x^2-9)

domain

f (x) = \frac{x - 5}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

\frac{2 ∣ x ∣ - x}{2 ∣ x ∣ + x}

f (x) = (ln (t + 1))

f (x) = \frac{- 4}{3 x} + \frac{1}{3 ( x - 3 )}

f (x) = \frac{8 x + 2}{6 x + 6}

lo g_{3} (x + 7)

What is the domain of f(x)=(x-5)/(x^2-9) ?
The domain of f(x)=(x-5)/(x^2-9) is x<-3\lor-3<x<3\lor x>3