What is the domain of (x+3)/(x^2+4x+3) ?

The domain of (x+3)/(x^2+4x+3) is x -1

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domain of (x+3)/(x^2+4x+3)

domain

\frac{x + 3}{x ^{2} + 4 x + 3}

x < - 3 or - 3 < x < - 1 or x > - 1

Interval Notation

(- \infty, - 3) \cup (- 3, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = - 3

The function domain

x < - 3 or - 3 < x < - 1 or x > - 1

1 - x^{2} - 1

f (x) = \frac{x + 2}{x + 8}

\frac{x + 2}{x ^{2} - x - 12}

f (x) = lo g_{10} (x^{2})

f (x) = lo g_{10} (x + 7)

What is the domain of (x+3)/(x^2+4x+3) ?
The domain of (x+3)/(x^2+4x+3) is x<-3\lor-3<x<-1\lor x>-1