What is the domain of y=(x-20)/(sqrt(x)+1) ?

The domain of y=(x-20)/(sqrt(x)+1) is x>= 0

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domain of y=(x-20)/(sqrt(x)+1)

domain

y = \frac{x - 20}{x + 1}

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

f (x) = \frac{5}{x + 9}

f (x) = ln (4 - x^{3})

ln (0)

\frac{3 x + 21}{6 x + 6}

f (x) = \frac{4 x - 5}{5 x - 20}

What is the domain of y=(x-20)/(sqrt(x)+1) ?
The domain of y=(x-20)/(sqrt(x)+1) is x>= 0