What is the domain of f(x)=log_{10}(1-x^2) ?

The domain of f(x)=log_{10}(1-x^2) is -1<x<1

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domain of f(x)=log_{10}(1-x^2)

domain

f (x) = lo g_{10} (1 - x^{2})

- 1 < x < 1

Interval Notation

(- 1, 1)

Solution steps

Find positive values for logs:

- 1 < x < 1

The function domain

- 1 < x < 1

f (x) = 1 + x - 2

f (x) = 2 (x^{4})^{2} + 3

f (x) = \frac{2 x ^{2} - 3 x}{x - 2}

f (x) = \frac{x ^{2} - 4}{x ^{2} - 9}

(x - 4)^{2} - 9

What is the domain of f(x)=log_{10}(1-x^2) ?
The domain of f(x)=log_{10}(1-x^2) is -1<x<1