What is the inverse of (9-x^{2/3})^{3/2} ?

The inverse of (9-x^{2/3})^{3/2} is (-\sqrt[3]{x^2}+9)^{3/2},-(-\sqrt[3]{x^2}+9)^{3/2}

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inverse of (9-x^{2/3})^{3/2}

inverse

(9 - x^{\frac{2}{3}})^{\frac{3}{2}}

Solution steps

y = (9 - x^{\frac{2}{3}})^{\frac{3}{2}}

Replace

x

with

y

x = (9 - y^{\frac{2}{3}})^{\frac{3}{2}}

Solve for

y, x = (9 - y^{\frac{2}{3}})^{\frac{3}{2}}

f (x) = 2 x^{2} - 10 x + 12

f (x) = \frac{4 x}{x - 2}

3 \cdot 1.3 5^{x}

arctan (\frac{x - 1}{x + 1})

f (x) = - 8 x^{2} - 2 x

What is the inverse of (9-x^{2/3})^{3/2} ?
The inverse of (9-x^{2/3})^{3/2} is (-\sqrt[3]{x^2}+9)^{3/2},-(-\sqrt[3]{x^2}+9)^{3/2}