What is the domain of (x^2+1)/(x^2-x+1) ?

The domain of (x^2+1)/(x^2-x+1) is -infinity <x<infinity

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domain of (x^2+1)/(x^2-x+1)

domain

\frac{x ^{2} + 1}{x ^{2} - x + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{2 x ^{2} + 1}{x ^{2} - 1}

x (1 - x^{2})^{2}

\frac{6 x ^{2}}{x ^{2} - 9}

y = \frac{- 2 ( x - 8 )}{8 - x}

f (x) = 6 x - x^{2} - 8

What is the domain of (x^2+1)/(x^2-x+1) ?
The domain of (x^2+1)/(x^2-x+1) is -infinity <x<infinity