What is the domain of sqrt(x^2-7x+6) ?

The domain of sqrt(x^2-7x+6) is x = 6

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domain of sqrt(x^2-7x+6)

domain

x^{2} - 7 x + 6

x \leq 1 or x \geq 6

Interval Notation

(- \infty, 1] \cup [6, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 1 or x \geq 6

The function domain

x \leq 1 or x \geq 6

f (x) = lo g_{10} (8 - 5 x)

f (x) = \frac{x}{x ^{3} - 125}

f (x) = \frac{2 x + 3}{x + 2}

f (x) = 3 cos (\frac{1}{x}) + 2

y = 3 x + 5

What is the domain of sqrt(x^2-7x+6) ?
The domain of sqrt(x^2-7x+6) is x<= 1\lor x>= 6