What is the domain of (x-4)/(2x^2+8x) ?

The domain of (x-4)/(2x^2+8x) is x 0

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domain of (x-4)/(2x^2+8x)

domain

\frac{x - 4}{2 x ^{2} + 8 x}

x < - 4 or - 4 < x < 0 or x > 0

Interval Notation

(- \infty, - 4) \cup (- 4, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 4

The function domain

x < - 4 or - 4 < x < 0 or x > 0

\frac{3 x - 2}{x + 5}

f (x) = \frac{4 x - 4}{x ^{2} + 2}

\frac{1}{x + 9} + 3

\frac{9}{9 - x}

f (x) = \frac{4}{( 4 + 4 x )}

What is the domain of (x-4)/(2x^2+8x) ?
The domain of (x-4)/(2x^2+8x) is x<-4\lor-4<x<0\lor x>0