What is the domain of f(x)=(2x^2+6x+4)/(-3x-5) ?

The domain of f(x)=(2x^2+6x+4)/(-3x-5) is x -5/3

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domain of f(x)=(2x^2+6x+4)/(-3x-5)

domain

f (x) = \frac{2 x ^{2} + 6 x + 4}{- 3 x - 5}

x < - \frac{5}{3} or x > - \frac{5}{3}

Interval Notation

(- \infty, - \frac{5}{3}) \cup (- \frac{5}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{5}{3}

The function domain

x < - \frac{5}{3} or x > - \frac{5}{3}

f (x) = \frac{x - 4}{x ^{2} + x - 20}

2 x - 3

- 2 x^{2} + 2 x - 4

\frac{1}{x - 13}

y - 2 = x + 5

What is the domain of f(x)=(2x^2+6x+4)/(-3x-5) ?
The domain of f(x)=(2x^2+6x+4)/(-3x-5) is x<-5/3 \lor x>-5/3