What is the domain of f(x)=(x^2)/(sqrt(x+1)) ?

The domain of f(x)=(x^2)/(sqrt(x+1)) is x>-1

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domain of f(x)=(x^2)/(sqrt(x+1))

domain

f (x) = \frac{x ^{2}}{x + 1}

x > - 1

Interval Notation

(- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

x > - 1

\frac{1}{1 - e ^{x}}

f (x) = lo g_{2} (x - 3) + 2

f (x) = \frac{x + 1}{1 - x}

\frac{1 - x ^{2}}{x}

\frac{2 + x ^{2}}{1 - x ^{2}}

What is the domain of f(x)=(x^2)/(sqrt(x+1)) ?
The domain of f(x)=(x^2)/(sqrt(x+1)) is x>-1