What is the domain of f(x)=(2x+2)/(sqrt(x^2+3x-40)) ?

The domain of f(x)=(2x+2)/(sqrt(x^2+3x-40)) is x 5

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domain of f(x)=(2x+2)/(sqrt(x^2+3x-40))

domain

f (x) = \frac{2 x + 2}{x ^{2} + 3 x - 40}

x < - 8 or x > 5

Interval Notation

(- \infty, - 8) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 8 or x \geq 5

Find undefined (singularity) points:

x = 5, x = - 8

Combine real regions and undefined points for final function domain

x < - 8 or x > 5

y = ∣ x + 3 ∣

f (x) = - 3^{x - 2} + 4

f (x) = e^{x + 1} + 2

\frac{x ^{2} - 1}{x ^{2} - 2 x - 3}

y = 2^{x} + 1

What is the domain of f(x)=(2x+2)/(sqrt(x^2+3x-40)) ?
The domain of f(x)=(2x+2)/(sqrt(x^2+3x-40)) is x<-8\lor x>5