What is the domain of f(x)=sqrt(x^2+10x+24) ?

The domain of f(x)=sqrt(x^2+10x+24) is x =-4

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domain of f(x)=sqrt(x^2+10x+24)

domain

f (x) = x^{2} + 10 x + 24

x \leq - 6 or x \geq - 4

Interval Notation

(- \infty, - 6] \cup [- 4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 6 or x \geq - 4

The function domain

x \leq - 6 or x \geq - 4

4 x - 4

4 x - 6

f (x) = - 2 x^{2} + 16 x - 31

f (x) = \frac{x + 4}{2 - x}

3 - x - 2 + x

What is the domain of f(x)=sqrt(x^2+10x+24) ?
The domain of f(x)=sqrt(x^2+10x+24) is x<=-6\lor x>=-4