What is the domain of f(x)=x+sqrt(x-1) ?

The domain of f(x)=x+sqrt(x-1) is x>= 1

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domain of f(x)=x+sqrt(x-1)

domain

f (x) = x + x - 1

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

f (x) = x 5

25 - 3 r

\frac{5 x + 2}{x - 5}

f (x) = \frac{6}{100 - x ^{2}}

f (x) = 2 + 4^{x - 1}

What is the domain of f(x)=x+sqrt(x-1) ?
The domain of f(x)=x+sqrt(x-1) is x>= 1