What is the domain of f(x)= x/(x^2+15x+54) ?

The domain of f(x)= x/(x^2+15x+54) is x -6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= x/(x^2+15x+54)

domain

f (x) = \frac{x}{x ^{2} + 15 x + 54}

x < - 9 or - 9 < x < - 6 or x > - 6

Interval Notation

(- \infty, - 9) \cup (- 9, - 6) \cup (- 6, \infty)

Solution steps

Find undefined (singularity) points:

x = - 6, x = - 9

The function domain

x < - 9 or - 9 < x < - 6 or x > - 6

y = x^{4}

∣ 2 - 5 x ∣

f (z) = e^{\frac{1}{z - 1}}

f (x) = 3 + \frac{4}{x ^{2}}

2^{x} + 4

What is the domain of f(x)= x/(x^2+15x+54) ?
The domain of f(x)= x/(x^2+15x+54) is x<-9\lor-9<x<-6\lor x>-6