What is the domain of f(x)=2+sqrt(6+9x) ?

The domain of f(x)=2+sqrt(6+9x) is x>=-2/3

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domain of f(x)=2+sqrt(6+9x)

domain

f (x) = 2 + 6 + 9 x

x \geq - \frac{2}{3}

Interval Notation

[- \frac{2}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{2}{3}

The function domain

x \geq - \frac{2}{3}

e^{x - 1}

f (x) = \frac{x - 1}{2 - x}

(- 2 x)^{2}

ln ((x + 2) (x - 1)^{2})

h (x) = x - 4

What is the domain of f(x)=2+sqrt(6+9x) ?
The domain of f(x)=2+sqrt(6+9x) is x>=-2/3