What is the domain of f(x)=(x+4)^2-1 ?

The domain of f(x)=(x+4)^2-1 is -infinity <x<infinity

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domain of f(x)=(x+4)^2-1

domain

f (x) = (x + 4)^{2} - 1

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{1}{1 + e ^{- x}}

ln (x^{2} - 2 x)

f (x) = \frac{x - 3}{7 x}

f (x) = \frac{2 x ^{2} - 9}{x ^{2} - 9}

y = 2 csc (x)

What is the domain of f(x)=(x+4)^2-1 ?
The domain of f(x)=(x+4)^2-1 is -infinity <x<infinity