What is the domain of sqrt(t^2-4) ?

The domain of sqrt(t^2-4) is t = 2

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domain of sqrt(t^2-4)

domain

t^{2} - 4

t \leq - 2 or t \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

t \leq - 2 or t \geq 2

The function domain

t \leq - 2 or t \geq 2

g (x) = ln (x - x^{3})

f (x) = 5 x^{2} - ∣ 5 x ∣

t^{2} - 5

\frac{- 2 - x}{x - 1}

ln (3 - ln (x))

What is the domain of sqrt(t^2-4) ?
The domain of sqrt(t^2-4) is t<=-2\lor t>= 2