What is the domain of (x^2+4x)/(sqrt(6-x)) ?

The domain of (x^2+4x)/(sqrt(6-x)) is x<6

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domain of (x^2+4x)/(sqrt(6-x))

domain

\frac{x ^{2} + 4 x}{6 - x}

x < 6

Interval Notation

(- \infty, 6)

Solution steps

Find non-negative values for radicals:

x \leq 6

Find undefined (singularity) points:

x = 6

Combine real regions and undefined points for final function domain

x < 6

f (x) = e^{x} + 4

f (x) = \frac{2 x - 6}{x + 9}

\frac{8}{x + 2}

f (x) = \frac{3 x + 4}{- x ^{2} - 2 x + 8}

2 x - 3

What is the domain of (x^2+4x)/(sqrt(6-x)) ?
The domain of (x^2+4x)/(sqrt(6-x)) is x<6