What is the domain of f(t)=arcsin(2t-3) ?

The domain of f(t)=arcsin(2t-3) is 1<= t<= 2

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domain of f(t)=arcsin(2t-3)

domain

f (t) = arcsin (2 t - 3)

1 \leq t \leq 2

Interval Notation

[1, 2]

Solution steps

Find known functions domain restrictions:

1 \leq t \leq 2

The function domain

1 \leq t \leq 2

y = 1 - 15 - 2 x - x^{2}

\frac{2 - 3 x}{x + 1}

y = 3 sin (2 x + 4) - 2

ln (1 + x)

\frac{2 x}{3 x}

What is the domain of f(t)=arcsin(2t-3) ?
The domain of f(t)=arcsin(2t-3) is 1<= t<= 2