What is the domain of f(x)=(sqrt(x+3))/(x-8) ?

The domain of f(x)=(sqrt(x+3))/(x-8) is -3 8

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domain of f(x)=(sqrt(x+3))/(x-8)

domain

f (x) = \frac{x + 3}{x - 8}

- 3 \leq x < 8 or x > 8

Interval Notation

[- 3, 8) \cup (8, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 3

Find undefined (singularity) points:

x = 8

Combine real regions and undefined points for final function domain

- 3 \leq x < 8 or x > 8

5 + x

\frac{1 + 2 x}{x - 1}

f (x) = 2 (2)^{x} - 5

\frac{1}{5.7 x - 8.1 x ^{2}}

- \frac{1}{2} x + 4

What is the domain of f(x)=(sqrt(x+3))/(x-8) ?
The domain of f(x)=(sqrt(x+3))/(x-8) is -3<= x<8\lor x>8