What is the domain of ln((2x)/(x+1)) ?

The domain of ln((2x)/(x+1)) is x 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of ln((2x)/(x+1))

domain

ln (\frac{2 x}{x + 1})

x < - 1 or x > 0

Interval Notation

(- \infty, - 1) \cup (0, \infty)

Solution steps

Find positive values for logs:

x < - 1 or x > 0

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x > 0

\frac{x - 5}{2}

\frac{x + 5}{2 x - 4}

f (x) = \frac{3 x}{x ^{2} - 121}

\frac{6 x - 25}{- 5 x + 41}

f (x) = 4^{x} + 3

What is the domain of ln((2x)/(x+1)) ?
The domain of ln((2x)/(x+1)) is x<-1\lor x>0