What is the domain of f(x)=(sqrt(x-2))/(x-4) ?

The domain of f(x)=(sqrt(x-2))/(x-4) is 2 4

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domain of f(x)=(sqrt(x-2))/(x-4)

domain

f (x) = \frac{x - 2}{x - 4}

2 \leq x < 4 or x > 4

Interval Notation

[2, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 4

Combine real regions and undefined points for final function domain

2 \leq x < 4 or x > 4

f (x) = 16 - 4 x^{2}

(x + 1)^{3}

- x - 3

y = x + 2

\frac{x + 3}{x ^{2} - 1}

What is the domain of f(x)=(sqrt(x-2))/(x-4) ?
The domain of f(x)=(sqrt(x-2))/(x-4) is 2<= x<4\lor x>4