What is the domain of y=(x+1)/(x-1) ?

The domain of y=(x+1)/(x-1) is x 1

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domain of y=(x+1)/(x-1)

domain

y = \frac{x + 1}{x - 1}

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

- 2 x - 3

- 2 x - 1

\frac{x}{5 x - 4}

f (x) = ∣ x + 4 ∣

f (x) = \frac{3 x + 1}{x - 2}

What is the domain of y=(x+1)/(x-1) ?
The domain of y=(x+1)/(x-1) is x<1\lor x>1