What is the domain of f(x)=(x^2-9)/3 ?

The domain of f(x)=(x^2-9)/3 is -infinity <x<infinity

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domain of f(x)=(x^2-9)/3

domain

f (x) = \frac{x ^{2} - 9}{3}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{- 4 - 5 x}{6 x - 1}

f (x) = x^{l n (x)}

f (x) = 2 + 3 x^{2} - x^{3}

f (x) = \frac{1 - 6 x + 9 x ^{2}}{3 x - 1}

f (x) = \frac{4 x + 10}{x + 3}

What is the domain of f(x)=(x^2-9)/3 ?
The domain of f(x)=(x^2-9)/3 is -infinity <x<infinity