What is the domain of f(x)=-sqrt(x^2-16) ?

The domain of f(x)=-sqrt(x^2-16) is x = 4

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domain of f(x)=-sqrt(x^2-16)

domain

f (x) = - x^{2} - 16

x \leq - 4 or x \geq 4

Interval Notation

(- \infty, - 4] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 4

The function domain

x \leq - 4 or x \geq 4

f (x) = 5 x^{2} + 11 g (x) = x + 2

\frac{x ^{3} + x}{x ^{2} - 1}

f (x) = \frac{1 - x}{x ^{2} - 4}

f (x) = 3 + \frac{2}{x}

f (x) = 3 x - 11

What is the domain of f(x)=-sqrt(x^2-16) ?
The domain of f(x)=-sqrt(x^2-16) is x<=-4\lor x>= 4