What is the domain of f(x)=sqrt(x^2+x-6) ?

The domain of f(x)=sqrt(x^2+x-6) is x = 2

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domain of f(x)=sqrt(x^2+x-6)

domain

f (x) = x^{2} + x - 6

x \leq - 3 or x \geq 2

Interval Notation

(- \infty, - 3] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 2

The function domain

x \leq - 3 or x \geq 2

2 x + 3 y = 6

f (x) = 5 + x - 2

f (x) = \frac{x + 2}{x ^{2} - 4 x + 4}

y = 0.7 5^{x}

What is the domain of f(x)=sqrt(x^2+x-6) ?
The domain of f(x)=sqrt(x^2+x-6) is x<=-3\lor x>= 2