What is the domain of sqrt(x^2-6x+8) ?

The domain of sqrt(x^2-6x+8) is x = 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of sqrt(x^2-6x+8)

domain

x^{2} - 6 x + 8

x \leq 2 or x \geq 4

Interval Notation

(- \infty, 2] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 2 or x \geq 4

The function domain

x \leq 2 or x \geq 4

y = \frac{4}{3} x + 7 - 5

\frac{5 x}{8 x - 1}

f (x) = \frac{- 2 x + 5}{3}

f (x) = \frac{x + 7}{x - 7}

f (x) = \frac{x + 7}{x - 6}

What is the domain of sqrt(x^2-6x+8) ?
The domain of sqrt(x^2-6x+8) is x<= 2\lor x>= 4