What is the domain of f(x)=x^2+sqrt(x) ?

The domain of f(x)=x^2+sqrt(x) is x>= 0

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domain of f(x)=x^2+sqrt(x)

domain

f (x) = x^{2} + x

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

f (x) = \frac{2 x ^{2} - 6 x}{x ^{2} - 2 x - 3}

f (x) = 2 x + 2

f (x) = \frac{2 x ^{2} - 6 x + 4}{- 3 x + 5}

x^{2} + 10

f (x) = \frac{3 x - 2}{x + 2}

What is the domain of f(x)=x^2+sqrt(x) ?
The domain of f(x)=x^2+sqrt(x) is x>= 0