What is the domain of f(x)=sqrt(25-x^2)-2 ?

The domain of f(x)=sqrt(25-x^2)-2 is -5<= x<= 5

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domain of f(x)=sqrt(25-x^2)-2

domain

f (x) = 25 - x^{2} - 2

- 5 \leq x \leq 5

Interval Notation

[- 5, 5]

Solution steps

Find non-negative values for radicals:

- 5 \leq x \leq 5

The function domain

- 5 \leq x \leq 5

f (x) = ln (1 + x)

f (x) = \frac{x - 7}{4}

f (x) = \frac{x + 5}{x - 4}

f (x) = \frac{x ^{2} - 16}{x ^{2} - 11 x + 24}

f (x) = \frac{12 - ln ( 4 - x )}{x - 2}

What is the domain of f(x)=sqrt(25-x^2)-2 ?
The domain of f(x)=sqrt(25-x^2)-2 is -5<= x<= 5