What is the asymptotes of f(x)=(4x^2+6x+1)/(2x-3) ?

The asymptotes of f(x)=(4x^2+6x+1)/(2x-3) is Vertical: x= 3/2 ,Slant: y=2x+6

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asymptotes of f(x)=(4x^2+6x+1)/(2x-3)

asymptotes

f (x) = \frac{4 x ^{2} + 6 x + 1}{2 x - 3}

Vertical : x = \frac{3}{2}, Slant : y = 2 x + 6

Solution steps

Vertical asymptotes of

\frac{4 x ^{2} + 6 x + 1}{2 x - 3} : x = \frac{3}{2}

Horizontal Asymptotes of

\frac{4 x ^{2} + 6 x + 1}{2 x - 3} :

None

Slant Asymptotes of

\frac{4 x ^{2} + 6 x + 1}{2 x - 3} : y = 2 x + 6

Vertical : x = \frac{3}{2}, Slant : y = 2 x + 6

f (x) = 6 - x

f (x) = cos (x - \frac{π}{2})

f (x) = x^{2} ln (\frac{x}{6})

f (x) = \frac{8 e ^{x}}{e ^{x} - 6}

f (x) = \frac{2}{3 x - 1}

What is the asymptotes of f(x)=(4x^2+6x+1)/(2x-3) ?
The asymptotes of f(x)=(4x^2+6x+1)/(2x-3) is Vertical: x= 3/2 ,Slant: y=2x+6